What will be the unit vector in the direction of \(\vec{A}=5 \vec{i}+\vec{j}-2 \vec{k} \text{?}\)
1. \(\dfrac{5}{\sqrt{30}} \vec{i}+\dfrac{1}{\sqrt{30}} \vec{j}+\dfrac{2}{\sqrt{30}} \vec{k}\)
2. \(\dfrac{5}{\sqrt{30}} \vec{i}+\dfrac{1}{\sqrt{30}} \vec{j}-\dfrac{2}{\sqrt{30}} \vec{k}\)
3. \(\dfrac{5}{\sqrt{30}} \vec{i}-\dfrac{1}{\sqrt{30}} \vec{j}-\dfrac{2}{\sqrt{30}} \vec{k}\)
4. \(\dfrac{5}{\sqrt{30}} \vec{i}-\dfrac{1}{\sqrt{30}} \vec{j}+\dfrac{2}{\sqrt{30}} \vec{k}\)
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Subtopic: Resolution of Vectors |
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If a vector has a magnitude equal to that of \(\vec{A}=4 \hat{i}+3\hat{j}\) and is parallel to \(\vec{B}=4 \hat{i}+3\hat{j},\) then the \(x\) and \(y\) components of this vector in the first quadrant are \(x\) and \(3\) respectively. Then the value of \(x\) is:
1. \(3\)
2. \(4\)
3. \(5\)
4. \(2\)
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Subtopic: Resolution of Vectors |
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